X^2 y^2 2gx 2fy c=0 differential equation 221206-X^2+y^2+2gx+2fy+c=0 differential equation

Obtain the differential equation of the family of circles x^2 y^2 2gx 2fy c = 0 ;

X^2+y^2+2gx+2fy+c=0 differential equation-Let C_1x^2y^22gx2fyc=0 and C_2=x^2y^22gx2fyc_1=0 Now note that C_1=(xg)^2(yf)^2=f^2g^2c and C_2=(xg)^2(yf)^2=f^2g^2c_1 Now assuming that c\ge c_1, C_1 is contained in To ask Unlimited Maths doubts download Doubtnut from https//googl/9WZjCW Theorem Prove that the equation `x^2y^22gx2fyc=0` always represent a circle whose centre is ` (g;f)` and radius

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Hope you like the test given above for IIT JAM Mathematics 23 of Topic – Exact Differential Equations of the Chapter Differential Equations To get more Information about any exam, Previous Question Papers , Study Material, Book PDF, Notes etc for free, do share the post with your friends and Follow and Join us on other Platforms links are given below to get moreN/AThe equation x^(2) y^(2) 2gx 2fy c = 0 represents a circle of nonzero radius , if The equation x^(2) y^(2) 2gx 2fy c = 0 represents a circle of nonzero radius , if Books

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